# Line slope calculator x+9y=19

**Straight line given by points A[1; 2] and B[10; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.1111x+2.1111

**Canonical form of the line equation:**x+9y-19 = 0

**Parametric form of the line equation:**

x = 9t+1

y = -t+2 ; t ∈ R

**Slope:**m = -0.1111

**Slope angle of line: φ =**-6°20'25″ = -0.1107 rad

**X intercept:**x

_{0}= 19

**Y intercept:**y

_{0}= q = 2.1111

**Distance line from the origin:**d

_{0}= 2.0982

**The length of the segment AB: |AB| =**9.0554

**Vector: AB =**(9; -1)

**Normal vector: n =**(1; 9)

**Midpoint of the segment AB: M =**[5.5; 1.5]

**Perpendicular Bisector equation:**9x-y-48 = 0

**Vector OA = (1; 2) ; |OA| = 2.2361**

**Vector OB = (10; 1) ; |OB| = 10.0499**

**Scalar product OA .OB = 12**

**Angle ∠ AOB = 57°43'28″ = 1.0075 rad**